All practice pages

Chemical equations

Balancing, the five kinds of reaction, ionic compounds in water, the solubility rules, and a precipitation reaction written three ways. The in-class sheet, practice, rounds of ten, and an atom counter for the homework.

Chapter 4, part 1

Chemical equations and precipitation reactions, from slides 2 to 15 of the Chapter 4 partial notes and the first lecture video.

Homework: Writing and Balancing Chemical Equations and Classifying Chemical Reactions, in the Chapter 4 folder.

A chemical equation says what reacts and what forms. The formulas say which substances, the coefficients in front say how many of each, and the states say what form each one is in.

Reading an equation

O₂(g) + 2NO(g) → 2NO₂(g)

Reactants and products

Reactants on the left, products on the right, and the arrow reads “react to form”.

Coefficients

The 2 in 2NO means two molecules, or two moles. With no number in front, the coefficient is 1.

States

(s) solid, (l) liquid, (g) gas, (aq) dissolved in water. Heat is a Δ above the arrow.

Balancing, step by step

  1. Write the skeleton equation with the correct formula for every substance. Hydrogen gas reacts with oxygen gas to form steam:

    H₂(g) + O₂(g) → H₂O(g)

  2. Balance the atoms with coefficients. Oxygen is 2 on the left and 1 on the right, so put a 2 in front of the water. That makes 4 hydrogens on the right, so put a 2 in front of the hydrogen.

    2H₂(g) + O₂(g) → 2H₂O(g)

  3. Make the coefficients whole numbers if they are not, and check every element again: 4 H and 2 O on each side.

  4. Give the states and any conditions, such as Δ above the arrow when heat is needed.

Never change a formula

Changing a subscript makes a different substance: H₂O₂ is hydrogen peroxide, not water.

Never add or remove a substance

The equation has the substances the reaction has. Only the coefficients move.

Most complex compound first

Start with the compound with the most atoms and save elements, such as O₂, for last: they change nothing else.

Ions that travel together

A polyatomic ion found on both sides, such as PO₄³⁻ or SO₄²⁻, can be balanced as one unit.

  1. Ethane burns in oxygen. Carbon and hydrogen first: 2 C means 2CO₂, and 6 H means 3H₂O.

    C₂H₆ + O₂ → 2CO₂ + 3H₂O

  2. That leaves 4 + 3 = 7 oxygen atoms on the right, which is 7/2 O₂. A fraction is fine for a moment.

    C₂H₆ + 72O₂ → 2CO₂ + 3H₂O

  3. Double everything to clear the fraction, step 3 of the notes.

    2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Five kinds of reaction

CombinationA + B → ABTwo or more substances make one: 2Mg(s) + O₂(g) → 2MgO(s)
DecompositionAB → A + BOne substance breaks into two or more: 2KClO₃(s) → 2KCl(s) + 3O₂(g)
Single displacementA + BC → AC + BAn element takes another’s place: Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
Double displacement (metathesis)AB + CD → AD + CBTwo compounds swap partners: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)
Combustionfuel + O₂ → oxidesMost have O₂ as a reactant; a hydrocarbon burns to CO₂ and H₂O: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

Ionic compounds in water

A soluble ionic compound dissociates: it comes apart into its ions, and water molecules gather round each one. That is solvation.

Na₂SO₄(s) → 2Na⁺(aq) + SO₄²⁻(aq)

Subscripts become coefficients

The 2 in Na₂SO₄ says two sodium ions: 2Na⁺.

Polyatomic ions stay whole

Sulfate stays SO₄²⁻. It does not fall apart into sulfur and oxygen.

Charges balance

2(+1) + (−2) = 0, the same as the neutral compound on the left.

The solubility rules

There is no way to predict solubility from the charges alone, so the course uses rules drawn from observation: Table 4.1 of the notes.

Soluble

  1. All compounds of the alkali metals (Group 1A) are soluble.
  2. All salts containing NH₄⁺, NO₃⁻, ClO₄⁻, ClO₃⁻ and C₂H₃O₂⁻ are soluble.
  3. All chlorides, bromides and iodides are soluble, except when combined with Ag⁺, Pb²⁺ and Hg₂²⁺.
  4. All sulfates are soluble, except those of Pb²⁺, Ca²⁺, Sr²⁺, Hg₂²⁺ and Ba²⁺.

Insoluble

  1. All metal hydroxides (OH⁻) and metal oxides (O²⁻) are insoluble, except those of Group 1A and of Ca²⁺, Sr²⁺ and Ba²⁺. A metal oxide that does dissolve reacts with water to give the hydroxide: Na₂O(s) + H₂O → 2NaOH(aq).
  2. All salts that contain PO₄³⁻, CO₃²⁻, SO₃²⁻ and S²⁻ are insoluble, except those of Group 1A and NH₄⁺.

Mercury(I) is the pair Hg₂²⁺, which is why the 2 matters. The Tools tab looks up any pair of ions against these six rules.

Precipitation reactions

Two solutions of soluble ionic compounds are mixed, and an insoluble product forms: the precipitate. Its forming is the driving force, because it takes ions out of the solution.

  1. Note the ions in each solution. Silver nitrate and sodium chromate:

    Ag⁺, NO₃⁻ and Na⁺, CrO₄²⁻

  2. Swap partners, as in a double displacement, and write the new compounds with the charges balanced.

    Ag₂CrO₄ and NaNO₃

  3. Use the solubility rules. Sodium nitrate dissolves (rules 1 and 2). Chromate is not in the table; silver chromate is the red-brown precipitate.

Molecular equation2AgNO₃(aq) + Na₂CrO₄(aq) → Ag₂CrO₄(s) + 2NaNO₃(aq)Every compound written whole, with its state.
Total ionic equation2Ag⁺(aq) + 2NO₃⁻(aq) + 2Na⁺(aq) + CrO₄²⁻(aq) → Ag₂CrO₄(s) + 2Na⁺(aq) + 2NO₃⁻(aq)Every soluble ionic compound split into its ions. The solid stays together.
Net ionic equation2Ag⁺(aq) + CrO₄²⁻(aq) → Ag₂CrO₄(s)The spectator ions, Na⁺ and NO₃⁻, appear unchanged on both sides and are cancelled.
Balanced twice over

A balanced ionic or net ionic equation has the same atoms on each side and the same total charge on each side.

Split only what dissolves

Only soluble ionic compounds, written (aq), are written as ions. Solids, liquids and gases stay whole.

No precipitate, no reaction

If both new combinations are soluble, every ion is a spectator and nothing happens.

  1. Sodium iodide with lead(II) nitrate. Swap partners: lead(II) iodide and sodium nitrate. Iodides are soluble except with Pb²⁺ (rule 3), so lead(II) iodide is the precipitate.

    2NaI(aq) + Pb(NO₃)₂(aq) → PbI₂(s) + 2NaNO₃(aq)

  2. Split the three soluble compounds into ions.

    2Na⁺(aq) + 2I⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq) → PbI₂(s) + 2Na⁺(aq) + 2NO₃⁻(aq)

  3. Cancel the spectators, 2Na⁺ and 2NO₃⁻.

    Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)