All practice pages/Interatomic theory
Formulas, models, empirical against molecular, isomers, ions and the lattice, hydrates, and naming both directions.
Wednesday 23 September
Monday laid out the rules: ionic against covalent, the charges you read off a column, Roman numerals, and the Greek prefixes. Parts d and e of the sheet are set for Wednesday, and the rest of it is here to work through.
Homework: the two open Chapter 2 sets, 11:59 pm on Sunday the 27th. Lumen types a subscript as an underscore, CaCl_2.
Read what a compound is made of first. Whether the atoms trade electrons or share them settles the counting, the drawing and the name.
A chemical formula gives the elements in a substance and how many atoms of each go into one unit of it. Three marks do all the work: a subscript belongs to the symbol in front of it, a subscript after a bracket multiplies everything inside the bracket, and a raised dot adds whole water molecules on the end.
| Formula | Atoms in one unit | Where they come from |
|---|---|---|
| H₂O | 2 hydrogen, 1 oxygen | A symbol with no subscript means one of it. |
| Ca(NO₃)₂ | 1 calcium, 2 nitrogen, 6 oxygen | The 2 outside multiplies the N and the O₃ both. |
| (NH₄)₂SO₄ | 2 nitrogen, 8 hydrogen, 1 sulfur, 4 oxygen | Two ammoniums at four hydrogens each. |
| CuSO₄ · 5H₂O | 1 copper, 1 sulfur, 9 oxygen, 10 hydrogen | Five waters ride along: 10 more H and 5 more O. |
Try
Methane, five times over. Each drawing keeps what the one before it had and adds something: connections, then direction, then size. The formula on its own says nothing about shape, which is the whole reason the other four exist.
A ball and stick model is not a photograph. The sticks are not real objects and their length is not to scale, and the space filling model is the closest of the five to how a molecule behaves when it bumps into another one.
Most elements are written as a bare symbol, one atom at a time: sodium is Na, copper is Cu, argon is Ar. Seven are never found that way. In nature they come in pairs, and the pair is what you write.
H₂ N₂ O₂ F₂ Cl₂ Br₂ I₂
Learn these seven. They sit in a rough 7 on the table, with hydrogen tacked on. Write them as pairs whenever you mean the pure element, so chlorine gas is Cl₂ and not Cl.
A few elements go further and bond in larger groups. Sulfur comes as a ring of eight, S₈, and white phosphorus as a cluster of four, P₄.
This is the trap in the book's first question of the section: O and O₂ are not the same thing on paper. O is the element, and one atom of it. O₂ is a molecule with two atoms in it. Sulfur tempts you into writing S₂ by the same pattern, and sulfur is S₈.
The molecular formula counts the atoms in one molecule. The empirical formula gives the same atoms in the smallest whole number ratio. Divide every subscript by the largest number that goes into all of them.
| Compound | Molecular | Divide by | Empirical |
|---|---|---|---|
| glucose | C₆H₁₂O₆ | 6 | CH₂O |
| caffeine | C₈H₁₀N₄O₂ | 2 | C₄H₅N₂O |
| hydrogen peroxide | H₂O₂ | 2 | HO |
| benzene | C₆H₆ | 6 | CH |
| sucrose | C₁₂H₂₂O₁₁ | 1 | C₁₂H₂₂O₁₁ |
Sucrose is the reminder that plenty of formulas are already in lowest terms. Nothing but 1 goes into 12, 22 and 11 together, so the two formulas are the same, and that is a real answer.
Going the other way is not possible on its own. CH₂O is the empirical formula of glucose, C₆H₁₂O₆, and also of acetic acid, C₂H₄O₂. The ratio does not tell you which molecule you have.
Ionic compounds only ever get written as the empirical formula, because there is no molecule to count. NaCl means one sodium for every chlorine, not a pair sitting together.
Two spots to be careful: H₂O₂ goes to HO, not to H or HO₂, and a subscript of 1 is never written. C₉H₈O₄, aspirin, has nothing in common between 9, 8 and 4, so it stays as it is.
The homework hands you a structure and asks for both formulas. Count every atom in the picture, including the hydrogens hanging off the ends, and that is the molecular formula. Then reduce it, and that is the empirical one.
Two of the four reduce to themselves, which is the point of putting them here. An answer of "it stays as it is" is a real answer, and the question is written to see whether you check.
Isomers have the same molecular formula and are not the same compound. C₃H₆O₂ is two different liquids depending on how the atoms are joined, and they do not behave alike.
| Propanoic acid | Methyl ethanoate | |
|---|---|---|
| Formula | C₃H₆O₂ | C₃H₆O₂ |
| Density | 0.9954 g/mL | 0.92 g/mL |
| Melting point | −20.8 °C | −98.05 °C |
| Boiling point | 141 °C | 57 °C |
A gap of 84 degrees in boiling point, from the same nine atoms.
Structural isomers are joined up differently. Propanoic acid and methyl ethanoate are one pair. C₂H₆O is another: ethanol, with its oxygen on the end, and dimethyl ether, with the oxygen in the middle.
Spatial isomers are joined up the same way and sit differently in space. L‑alanine and D‑alanine are mirror images that cannot be laid on top of each other, the way your hands cannot.
Not every formula has an isomer. Two carbons and six hydrogens can only be put together one way, so C₂H₆ is ethane and nothing else.
An ion is an atom that has lost or gained electrons. The protons never move, so the charge is only ever an electron count. A main group element takes whatever charge lands it on the electron count of the nearest noble gas, which is why the charge can be read straight off the group.
| Atom | Electrons | What it does | Ends up like | Ion |
|---|---|---|---|---|
| sodium | 11 | loses 1 | neon, 10 | Na⁺ |
| magnesium | 12 | loses 2 | neon, 10 | Mg²⁺ |
| aluminum | 13 | loses 3 | neon, 10 | Al³⁺ |
| nitrogen | 7 | gains 3 | neon, 10 | N³⁻ |
| oxygen | 8 | gains 2 | neon, 10 | O²⁻ |
| chlorine | 17 | gains 1 | argon, 18 | Cl⁻ |
| calcium | 20 | loses 2 | argon, 18 | Ca²⁺ |
A cation is positive, made by losing electrons, and keeps the element's name: the calcium ion. An anion is negative, made by gaining them, and takes an -ide ending: the chloride ion.
Metals are on the left and have few electrons to shed, so they go positive. Nonmetals are on the right and are close to a full count already, so they go negative. Group 8A is already there and forms no ions worth naming.
This is a main group rule only. The transition metals in the B groups do not have one predictable charge, which is exactly why their names carry a Roman numeral.
Opposite charges pull on each other, and that pull is the ionic bond. It does not join two ions into a private pair. Every sodium ion in table salt is surrounded by chloride ions, every chloride by sodium ions, and the pattern repeats in all three directions for as far as the crystal goes.
So there is no molecule of NaCl to point at. What the formula gives is a formula unit: the smallest whole number ratio of the ions, and enough of each to make the charge come out to zero.
Say formula unit for ionic compounds and molecule for covalent ones. The exam has asked which word belongs.
| Put together | Ions | Charge to cancel | Formula unit |
|---|---|---|---|
| sodium and chlorine | Na⁺ and Cl⁻ | 1 and 1, already even | NaCl |
| magnesium and chlorine | Mg²⁺ and Cl⁻ | 2+ needs two 1− | MgCl₂ |
| magnesium and oxygen | Mg²⁺ and O²⁻ | 2 and 2, already even | MgO |
The three the lecture works through. Mg²⁺ with O²⁻ is MgO and never Mg₂O₂, because the ratio has to come down to the smallest whole numbers.
| Ionic | Covalent | |
|---|---|---|
| Held by | pull between + and − charges | a shared pair of electrons |
| Smallest piece | a formula unit | a molecule |
| Made from | a metal and a nonmetal | two nonmetals |
| Formula comes from | charges cancelling | the prefixes in the name |
The subscripts are whatever makes the charges add to zero, in the smallest whole numbers. Mg²⁺ with S²⁻ is MgS, never Mg₂S₂. Parentheses go around a polyatomic ion only when there is more than one of it.
The other direction, and the one the homework leans on hardest: given the formula, write the two ions with their charges. A covalent compound has no ions to write, which is half of what the question is testing.
| Compound | Cation | Anion |
|---|---|---|
| BaO | Ba²⁺ | O²⁻ |
| Na₂O | Na⁺ | O²⁻ |
| (NH₄)₂CO₃ | NH₄⁺ | CO₃²⁻ |
| Sr(H₂PO₄)₂ | Sr²⁺ | H₂PO₄⁻ |
| NF₃ | covalent, so no ions | |
| IBr | covalent, so no ions | |
The subscript is a count, not a charge. The 2 outside the bracket in Sr(H₂PO₄)₂ says there are two dihydrogen phosphate ions. Each one still carries 1−. Writing H₂PO₄²⁻ because of that 2 is the mistake the question is set to catch.
Work it from the side you know. Strontium is group 2, so it is Sr²⁺; the compound is neutral, so the two anions have to carry 2− between them, which is 1− each.
An ion made of one atom, like Ba²⁺ or O²⁻, is a monatomic ion. One built from a central atom with oxygens around it, like CO₃²⁻ or SO₄²⁻, is an oxyanion, and that is the family the -ate and -ite endings name.
Some ionic compounds crystallise with water caught in the lattice. The water is written after a raised dot, with a number in front of it for how many go with each formula unit, and the name ends in a Greek prefix plus the word hydrate.
| Formula | Name |
|---|---|
| LiClO₄ · 3H₂O | lithium perchlorate trihydrate |
| CuSO₄ · 5H₂O | copper(II) sulfate pentahydrate |
| MgSO₄ · 7H₂O | magnesium sulfate heptahydrate |
| CoCl₂ · 6H₂O | cobalt(II) chloride hexahydrate |
| Na₂CO₃ · 10H₂O | sodium carbonate decahydrate |
Name the compound exactly as you would without the water, Roman numeral and all, then add the prefix and hydrate.
That water is not held tightly. Heat the crystal and it leaves as steam, and what is left is the anhydrous compound. Copper(II) sulfate is the one everybody remembers: blue with its five waters, white without them.
The prefixes are the same ones covalent names use, mono through deca, and here the mono is kept: a compound with one water is a monohydrate.
Wednesday's lab is the dehydration of a hydrate, where the water driven off is weighed to find how many went with each formula unit. Worth having the dot straight before then.
Two nonmetals have no reason to hand electrons over, because neither one is inclined to give them up. Instead they share a pair, and the shared pair is the covalent bond. What it makes is a real molecule, a fixed group of atoms with a size and a shape.
H₂O CH₄ CO CO₂
Because nothing has to cancel, the formula cannot be worked out from charges. There is no rule that says carbon and oxygen must meet one to one, and so CO and CO₂ both exist and are different gases.
That is why covalent names carry prefixes and ionic names do not. The prefix is carrying the information that the charges would have carried.
Electrons are handed over, and the pull between the ions that are left is the ionic bond. Charges cancel, so no prefixes are ever used. Ammonium takes the metal's place, and the piece you count is a formula unit, never a molecule.
NaCl, Ca₃N₂, (NH₄)₂SO₄Neutral atoms share a pair of electrons, and the shared pair is the covalent bond. What it makes is a molecule. The formula cannot be worked out from charges, so prefixes tell you how many of each.
CO, N₂O₄, P₂S₅Hydrogen ions bonded to a negative ion. The anion's ending decides the acid's ending.
HCl, H₂SO₄, HNO₂Metals sit on the left of the staircase and the nonmetals on the right. Ammonium, NH₄⁺, is not a metal but stands in for one, so (NH₄)₂SO₄ is ionic.
Where that rule bends
Silicon and arsenic are metalloids, neither one thing nor the other. SiCl₄ and AsCl₅ are covalent and take prefixes, so silicon tetrachloride, not silicon(IV) chloride.
CuCl₂ and CrCl₃ are ionic, but the charge cannot be read off the table. That is what the Roman numeral is for: copper(II) chloride, chromium(III) chloride. The numeral goes right against the name with no space: iron(III), never iron (III).
AlCl₃ is a metal with a nonmetal and still behaves covalently. The rule is a good guide rather than a law, and the book says so itself.
The homework asks this as often as it asks for a name, and the rules above give you nothing to answer with. It comes down to how hard the pieces are held together.
| Sodium chloride | Water | |
|---|---|---|
| Kind | ionic | covalent |
| Melts at | 801 °C | 0 °C |
| Boils at | 1413 °C | 100 °C |
Pulling a lattice of charges apart takes far more heat than separating molecules from one another, so ionic compounds are solids with high melting points and covalent ones are often gases, easily boiled liquids, or solids that melt low.
Conducting is the careful one. A solid ionic compound does not conduct: the ions are locked in the lattice and nothing can move. Melt it, or dissolve it, and it conducts well, because now the ions can travel.
So the flat sentence "ionic compounds conduct electricity" is marked wrong. The one that is right says molten or dissolved.
Covalent compounds have no ions to move at all, so they generally do not conduct in any state. These are strong tendencies rather than laws, and the book hedges them the same way.
| Where it sits | Charge | Example |
|---|---|---|
| Group 1, the alkali metals | 1+ | Na⁺, K⁺ |
| Group 2, the alkaline earths | 2+ | Mg²⁺, Ca²⁺ |
| Group 13, aluminum | 3+ | Al³⁺ |
| Group 15 | 3− | N³⁻, P³⁻ |
| Group 16 | 2− | O²⁻, S²⁻ |
| Group 17, the halogens | 1− | Cl⁻, Br⁻ |
| Transition metals | What to write |
|---|---|
| Silver | always 1+, no numeral |
| Zinc | always 2+, no numeral |
| Cadmium, under zinc and the same in this respect | always 2+, no numeral |
| Iron, copper, cobalt, nickel, chromium, manganese, gold, mercury, titanium | Roman numeral for the charge, worked out from the anion |
| Tin and lead, which also take two charges | Roman numeral, tin(II) or tin(IV) |
Know these three. Silver 1+, zinc 2+ and aluminum 3+ are the metals whose charge never varies, so their names take no Roman numeral. Every other transition or post-transition metal needs one. Silver(I) chloride is accepted here as well, but silver chloride is the form the worksheet uses.
Mercury(I) is the odd one out. It travels as a pair of mercury ions sharing a single 2+ charge, written Hg₂²⁺, so mercury(I) chloride is Hg₂Cl₂ and not HgCl. Mercury(II) behaves normally.
An older set of names is still in use: ferrous and ferric for iron(II) and iron(III), cuprous and cupric for copper(I) and copper(II), stannous and stannic for tin(II) and tin(IV). The -ous ending is the lower charge and -ic the higher. Write the Roman numeral version unless you are asked for the old one.
Fe₂(SO₄)₃ has three sulfates at 2− each, so 6− in all, shared by two irons: iron(III) sulfate. The numeral is the charge on one metal ion, not the number of them.
Every other transition metal has a choice about how many electrons to give up, which is what the Roman numeral records. These three have only one way to go, and the configurations show it.
| Metal | Ion | Atom, then ion | What is left |
|---|---|---|---|
| silver | Ag⁺ | [Kr]4d¹⁰5s¹ → [Kr]4d¹⁰ | the single 5s electron goes and the d subshell is full |
| zinc | Zn²⁺ | [Ar]3d¹⁰4s² → [Ar]3d¹⁰ | both 4s electrons go, and again the d subshell is full |
| aluminum | Al³⁺ | [Ne]3s²3p¹ → [Ne] | all three outer electrons go, down to neon's core |
A full d subshell is hard to break into. Taking a further electron out of silver's or zinc's 4d or 3d costs far more energy than any bond gives back, so there is no second charge to choose between.
Aluminum is fixed for the plainer reason: it is a main group metal with three outer electrons, and losing all three leaves it with neon's electron count. That is the same rule that fixes sodium at 1+ and magnesium at 2+.
Cadmium sits directly under zinc, [Kr]4d¹⁰5s² down to [Kr]4d¹⁰, and behaves the same way. It is not one of the three to memorise, but its name takes no numeral either.
| Formula | Name |
|---|---|
| CO | carbon monoxide |
| SO₃ | sulfur trioxide |
| N₂O₄ | dinitrogen tetroxide |
| SF₆ | sulfur hexafluoride |
| XeCl₅ | xenon pentachloride |
A few compounds never get their systematic name. H₂O is water, NH₃ is ammonia, CH₄ is methane. Nobody says dihydrogen monoxide outside a joke, and the homework will not either.
The first element drops mono, so CO₂ is carbon dioxide and not monocarbon dioxide. Before oxide the a or o falls away: monoxide, tetroxide, pentoxide.
| Anion ending | Acid ending | Example |
|---|---|---|
| -ide | hydro- ... -ic acid | Cl⁻ chloride → HCl, hydrochloric acid |
| -ate | -ic acid | SO₄²⁻ sulfate → H₂SO₄, sulfuric acid |
| -ite | -ous acid | NO₂⁻ nitrite → HNO₂, nitrous acid |
Enough hydrogens go in front to cancel the charge, which is why carbonate and sulfate take two: H₂CO₃ and H₂SO₄. Acetic acid is the odd one written HC₂H₃O₂, with only the first hydrogen acidic.
One formula, two names. HCl as a pure compound is a gas, and by the covalent rules it is hydrogen chloride. Dissolved in water it is hydrochloric acid. The same goes for H₂S, hydrogen sulfide as a gas and hydrosulfuric acid in water. Either name is accepted here unless the question says which state it is in.
Aluminum is 3+ and sulfide is 2−. Two aluminums give 6+, so three sulfides are needed to cancel it.
Right atoms, wrong order. The positive ion is written first, always.
The charges already cancel one to one, so the subscripts have to come down to the smallest whole numbers.
Sodium oxalate is two Na⁺ with one C₂O₄²⁻. Halving every atom gives a real ratio and a wrong formula, because it breaks up the oxalate ion. Reduce the ratio of the ions, never the inside of one.
Oxide is O²⁻ and peroxide is O₂²⁻, two oxygens sharing one 2− charge. Sodium oxide is Na₂O, sodium peroxide is Na₂O₂. Hydroxide and peroxide both hold oxygen and neither is an oxyanion, which is why neither takes an -ate or an -ite.
Azide is three nitrogens sharing one negative charge. Nitride is one nitrogen carrying three. Subscript against superscript, and a different ion.
Nitride is the bare N³⁻ ion. Nitrate is the polyatomic NO₃⁻. One letter, a different compound.
The Chapter 2 in-class sheet: name it or write it, say whether it is ionic or covalent, and count the atoms of each element. One Check per compound, and the answer stays hidden until you have tried.
A new compound every time, asked the way the sheet asks it. Ionic compounds are built from the ion tables, so the mix keeps changing.